leet code

Given a string s, return the longest palindromic substring in s. A string is called a palindrome string if the reverse of that string is the same as the original string. Example 1: Input: s = “babad” Output: “bab” Explanation: “aba” is also a valid answer. Example 2: Input: s = “cbbd” Output: “bb” Solution : JavaScript : CPP […]

Find the length of the longest substring without repeated characters given a string s. Example 1: Input: s = “abcabcbb” Output: 3 Explanation: The answer is “abc”, with the length of 3. Example 2: Input: s = “bbbbb” Output: 1 Explanation: The answer is “b”, with the length of 1. Example 3: Input: s =

You are given two non-empty linked lists that each represent a non-negative integer. The digits are kept in reverse order, with each node containing only one digit. Add the two numbers together and return the total as a linked list. Except for the number 0 itself, you may presume that the two numbers do not

Provide the median of the two sorted arrays given two sorted arrays of sizes m and n, respectively. The entire complexity of the run time should be O(log (m+n)). Eg 1: Numbers1 = [1,3], Numbers2 = [2] Result: 2.00000 Explanation: the merged array equals [1,2,3], and the median is 2. Eg 2: Numbers1 = [1,2],

Leet Code 1. Two Sum : Hey there, coding enthusiasts! Welcome back to another exciting coding session. Today’s problem is a treat—literally! We’re going to solve the “two sum ” or “Leet Code .1‘ Time Complexity: C++: 1. Brute Force Approach: LeetCode 15 : Three (3) Sum Notice: This approach has a time complexity of

Given the head of a linked list, return the node where the cycle begins. If there is no cycle, return null. There is a cycle in a linked list if there is some node in the list that can be reached again by continuously following the next pointer. Internally, pos is used to denote the index of the node that tail’s next pointer is connected

Given the root of a binary tree, determine if it is a valid binary search tree (BST). A valid BST is defined as follows: Example 1: Input: root = [2,1,3] Output: true Solution

Given an array nums. We define a running sum of an array as runningSum[i] = sum(nums[0]…nums[i]). Return the running sum of nums. Example 1: Input: nums = [1,2,3,4] Output: [1,3,6,10] Explanation: Running sum is obtained as follows: [1, 1+2, 1+2+3, 1+2+3+4]. Example 2: Input: nums = [1,1,1,1,1] Output: [1,2,3,4,5] Explanation: Running sum is obtained as follows: [1, 1+1,