Leetcode 775. Find The Global and Local Inversions (Medium) : NileshBlog.Tech

Leetcode 775. Find The Global and Local Inversions :Hey there, coding enthusiasts! Welcome back to another exciting coding session. Today’s problem is a treat—literally! We’re going to solve the “Global and Local Inversions ” problem.

Table of Contents

Leet code 775 Code Explanation: Global and Local Inversions

1: We’re given an array of numbers called nums. The goal is to determine if every “local inversion” is also a “global inversion.”
2: A local inversion occurs when an element is larger than the next element.
- For example, in [1, 3, 2], the pair 3, 2 is a local inversion because 3 is larger than 2.
3: A global inversion is when the number of local inversions equals the number of global inversions.
- For example, in [1, 3, 2], there are 2 local inversions (3, 2 and 1, 3) and 2 global inversions (3, 2 and 1, 3).

4: The code iterates through each element in the nums array.
5: For each element, it calculates the absolute difference between the element’s value and its index. If this difference is greater than 1, it means there’s a non-local inversion, so we return false.
6: If we reach the end of the array without finding any non-local inversions, it means every local inversion is also a global inversion, and we return true.

Codes :

C++: Leetcode 775

#include <vector>
#include <cstdlib>

class Solution {
public:
    bool isIdealPermutation(std::vector<int>& nums) {
        for (int i = 0; i < nums.size(); ++i) {
            if (std::abs(nums[i] - i) > 1) return false;
        }
        return true;
    }
};

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Java:Leetcode 775

import java.util.*;

class Solution {
    public boolean isIdealPermutation(int[] nums) {
        for (int i = 0; i < nums.length; i++) {
            if (Math.abs(nums[i] - i) > 1) return false;
        }
        return true;
    }
}

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Python: Leetcode 775

class Solution:
    def isIdealPermutation(self, nums: List[int]) -> bool:
        for i in range(len(nums)):
            if abs(nums[i] - i) > 1:
                return False
        return True

JavaScript: Leetcode 775

class Solution {
    isIdealPermutation(nums) {
        for (let i = 0; i < nums.length; i++) {
            if (Math.abs(nums[i] - i) > 1) return false;
        }
        return true;
    }
}

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